BuilderBoi

\((9.6 \times 10^3) \times (6.7 \times 10^2) = (9.6 \times 6.7) \times (10^3 \times 10^2) = 64.32 \times 10^5 = \color{brown}\boxed{6.432 \times 10^6}\)

If 3 squares are red, the 5 squares have to be R _ R _ R. 

Can you take it from here?

Let's say we have the expression \(x^2 + 8x + 15\). 

We need 2 numbers that add to 8 and multiply to 15 (5 and 3).

Now, rewrite the expression: \(x^2 + 3x + 5x + 15\) (the order of the 3 and 5 doesn't matter)

Now, factor \(x^2 + 3x \) and \(5x + 15\): \(x(x+3)\) and \(5(x+3)\)

The equation is basically the sum of \(x(x+3) \) and \(5(x+3)\), so it is \((x+5)(x+3)\). (Notice how the constants in both terms are the numbers we chose initially (3 and 5). This can be used as a time saver once you get used to it.)

x=3

y=4

what about right triangle ABC?