GingerAle
14 Okt 2018

#5**0 **

*Good explanation. I actually prefer "literal" but for you I'll cop to pedantic, negative connotation notwithstanding.*

You don’t need to *cop to pedantic*; I do not think you are pedantic. You’re not pedantic in your solution presentations. (If you were, I’d be trolling the hell out of you.) Although apparently, (sometimes) you tend toward the literal for certain colloquialisms (and Latin word-order in certain phrases), you do not seem to be a diehard literalist. I think this quite funny, and I’m sure Gracie Allen would find it funny and endearing.

If someone asked you to bring them a cup of coffee, what would you bring to them?

A cup of coffee beans, a cup of ground coffee beans, a cup of dehydrated coffee extract, or a cup of brewed or instant coffee?

When I was eleven, I once brought a literal cup of coffee (the mug was two-thirds full of instant coffee crystals) to my mum, after she asked me to bring her a cup of coffee. My mum was greatly amused. The idea came to me after my Great Uncle Cosmo explained certain food chemistries to me. One of the examples was that a typical cup of coffee was 1.13% to 1.88% soluble vegetable matter (extracted from approximately 12 grams of ground coffee beans) and the rest was water. A cup of coffee is 98.75% water, but it’s called a cup of coffee. I never thought of it any other way until after my chemistry lesson from Cosmo.

GA

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GingerAle17 Jan 2022

#3**0 **

Here, I answer a very similar question. *If I choose four cards from a standard 52-card **deck, with** replacement, what is the probability that I will end up with all four Aces?*

**This solution post is based on the original:**

**The phrase “with replacement” is an explicit standard variation in the sampling method**. In this case, it means the card (no matter what it is) is replaced after it is drawn. It’s also important to note that the deck or selection process remains randomized after the card is replaced. **And, for the ultra pedantic minded (Ron)**, the value of the drawn card is recorded before its replacement into the deck. The records are then analyzed statistically for the probability of drawing four aces in sequence.

**This question is poorly written**. The primary defect is the phrase “*end up with four Aces,*” which is a colloquialism as used here. The capital “A” in “Aces” is nonstandard, and gives ambiguous emphases to the word aces. The word “all” is not used in this question, so the interpretation is biased toward any combination of Aces where one or more may be repeated.

**Rephrased as primer statistics question:**

If I choose four cards with replacement from a standard 52-card deck, what is the probability that I will select *four aces (of any suit)*?

A success in this experiment is four aces without regard to the suit.

\(\large \left(\dfrac{4}{52}\right)^4 = \dfrac{1}{28561}\)

Compare to the probability of selecting **four aces in four different suits, **where any other combination is a failure.

\(\large \dfrac{4}{52}*\dfrac{3}{52}*\dfrac{2}{52}*\dfrac{1}{52} =\dfrac{3}{913952}\)

GA

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GingerAle16 Jan 2022