the latus rec tum of parabola with equation (x-1)^2 = -16(y-4) coincides with the diameter of a circle. find equation of circle?
the latus rec tum of parabola with equation (x-1)^2 = -16(y-4) coincides with the diameter of a circle. find equation of circle?
Consider the parabola
it is of the from \((x-h)^2=4a(y-k)\)
Vertex \((h,k) = (1,4)\)
Focal length = a = -4
So it is a concave down parabola with focus point x=1 and y=4-4=0 focus (1,0)
The latus r****m is 16 units across and that is the diameter of the circle.
So the radius of the circle is 8 units and the centre of the circle is (1,0)
Circle:
\((x-1)^2+y^2=64\)
I just realized that you posted this question twice in quick succession.
PLEASE DO NOT DO THAT!
If your question has been there a long time then you can make a knew post that directs people to the original post.
Just copy and post the address of the original post in with a short explanation.
A long time is subjective but there should be either a day or around 20 questions between the two .