From the equation, we get x+7=Ax+A+Bx-2B.
A+B=1 and A-2B=7
Solving the equations will give us (A,B)=(3,-2).
The LA=2sl where s is the length of the square base. So the lateral surface area us D 126.
41.Degree:3, Number of terms:4
41.Degree:2, Number of terms:2
41.Degree:1, Number of terms:3
Let us say everything is positive. Now the ratio of a 45-45-90 triangle is 1:1:\(\sqrt2\) . But the ratio on the question is \(\frac{\sqrt3}{2}\)
The area of half the saded region is
144pi/6-36sqrt3=29pi-36sqrt3
Then, double that is 58pi-36sqrt3.
82. The discriminant is 0
83. The discriminant is greater than 0.
84. The discriminant is less than 0.
For a quadratic equation, the discriminant is \( \sqrt{b^2-4ac}\)
For an equation ax^2+bx+c.
With this you can plug in the values for each equation.
Easy, rectangle
Let us have d= the distance from home to school. Then the time at 12mi/hr is 5d because 12/60=1/5. Similarily 8/60=2/15 so it takes 15/2*d. Adding the times gives us 12.5d=60 so d=4.8mi. Thus it takes 4.8mi to school.
Can you provide a diagram plz.
If the numbers after x or y is powers, then they aren't lines.
\(7*\frac{2}{3}=\frac{14}{3}\). The smallest integer greater than 14/3 is \(5\)
