1: Cos(30) = 1/r therefore r = 2/sqrt3 and r^2 = 4/3
2:Area of equil Triang = (1/2)*(2)*sqrt((2^2)-(1^2))=sqrt3 therefore Area of rectangle = xy = sqrt3
3 Draw lines to the opposite vertices of the rectangle then add the area of the 4 triangles you just made inside the rectangle = total area:
2*area Tri A= 2*[(1/2)(x)sqrt(4/3 - (x^2)/4)
2*area Tri B= 2*[(1/2)(y)(x/2)]
4, Solve simultaneous equation to get x and y:
xy = sqrt3
(x)sqrt(4/3 - (x^2)/4) + (1/2)xy = sqrt3
--> If doing manually you substitute the first equation into the second then solve for x, followed by y, but since I'm lazy I used Wolfram alpha to do this for me and got
x≈2.16662 and y≈0.799424