Nice. :))
I really miss going on this forum more often.
Sadly, school is quite busy.
=^._.^=
Hello CCeed :))
Let angle B = x
angle A = 48
angle C = 132 - x
Since ABC ~ ACD
angle B = angle ACD = x
angle C = angle CDA = 132 - x
Since BC = BD
BCD = BDC
BCD + BDC + B = 180 degrees
BDC + BDC + x = 180 degrees
BDC = (180-x)/2
CDA + CDB = 180
132 - x + (180-x)/2 = 180
x = 28
I hope this helped. :))
Notice how we have 3 right triangles.
Use the pythagorean theorem to set up 3 equations.
How can we manipulate 2 of the equations to find the hypotenuse of the triangle?
I hope this helps. :))
To add a bit, the reason 12^n can't be wholly divisable by 20 is because 20 = 2^2 * 5 and 12 = 2^2 * 3.
That means that 12^n will only have factors of 2 and 3 (assuming n is an integer).
Therefore, it will never be able to divide out the 5 in 20.
If you know f(0), f(1) = f(0) + 2(1) + 1
Continue this process until you get to 4. :))
1. How many ways can you choose 3 points - how many ways can you choose 3 points that form a line?
2. If you connect two right isosceles triangle with a hypotenuse of 1 by the hypotenuse, you get a sqaure. Find the area of the square/2.
:))
Two digit numbers = 10-99
So there are (99-10+1) = 90 two digit numbers.
In every 6 consecutive numbers, there is one divisable by 6.
Can you take it from here?
Calculate 5! + 6! + 7! + 8! + 9! + 10! + 11! + 12!
What do you notice about 10!, 11!, and 12!?
1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
1 5 10 10 5 1
(a+b)^5 = a^5 + 5a^4b + 10a^3b^2 + 10a^2b^3 + 5ab^4 + b^5
5a^4b = 15
10a^3b^2 = 60
I think what guest means by 159 is that
x = 1
y = 5
z = 9
3(1+5+9) = 1*5*9