44118 = 3^b mod 65537
This says that
65537n + 44118 = 3b
There are infinite solutions to this...for instance....
Let n=3
Then we have
240729 = 3b
Taking the log of both sides, we have
log 240729 = log 3b .....and by a property of logs, we have
log 240729 = b*log3 ......and dividing both sides by log3, we have
log 240729/log 3 = b ≈ 11.2791630188882364
If we insist that both n and b be integers, I'm not sure how to solve this....(if it even has a solution).....(maybe Alan knows a method)