If f(x) = 3x + 3/x, then [f(x + h) - f(x)]/h =
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I'm making a broad assumption here, but in my experience, I believe you're trying to ultimately find the "difference quotient" ⇒ (the derivative of f(x) )
Let's simplify f(x) so we have
f(x) = [(3x2 + 3)/ x ] ...... then [f(x + h) - f(x)]/h =
([(3(x+h)2 + 3) / (x+h)] - [(3x2 + 3)/ x ]) / h =
([3x2 + 6xh + 3h2 + 3] / (x + h)] - [(3x2 + 3)/ x ]) / h =
[3x3 + 6x2h + 3xh2 + 3x - 3x3 - 3x2h -3x - 3h) / [(x)(x+h)(h)] =
[ 3x2h + 3xh2 - 3h) / [(x)(x+h)(h)] =
(3x2 ) / (x2 + xh) + 3h / (x+h) - 3 / [(x+h) (x)]
Now, let's take the limit of everything by letting h ⇒ 0 We get
3 - 3x-2
Note that this is just the derivative of f(x) (Which is what we were hoping for!!!)