nverse function of log6(x+1)
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I'm assuming that you mean this: y = log6 (x + 1)
Let's write this in exponential form, we have
6y = (x + 1) Now get x by itself
6y - 1 = x Now "exhange" x and y
6x - 1 = y Now, write y as f-1(x)
f-1(x) = 6x - 1
Notice that the "log" graph has a restricted domain ......i.e., x > -1
And notice that the range of the inverse is y (or f-1(x)) > -1