Let me add a little to Alan's answer.....Specifically....how do we arrive at those numbers??
Note we can write 2310 as
231 * 10 =
231 * 5 * 2 And there's a number theory property that says that if we can add the digits of a number, and that sum is divisible by three, then the number is divisible by three. So 231 = 2 + 3 + 1 = 6, and that's divisible by three. So, 231 is divisible by three. So we have
77 * 3 * 5 * 2 =
11 * 7 *3 * 5 * 2
Some answerers on here would also include "1" as a factor, but since "1" is a factor of any number, I usually don't include it. But, if you want to throw it into the mix, be my guest. To be "technically" correct, I suppose it should be included!!