Line k intersected on the left side has an equasion; (2x+8)
Line k intersected on the right side has an equasion; (5x-10)
Line L intersected on the left side has an equasion; (3x+42)
Line L intersected on the right side has an equasion;(x+34)
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I'm not sure, but I think you are tyring to find some angles, here
We have that, for line K .... [ 2x + 8 ] + [ 5x - 10] = 180
Simplifying, we have ....7x - 2 = 180 add 2 to both sides
7x = 182 divide both sides by 7
x = 26
So.....the angle on the left side of line K = 2(26) + 8 = 52 + 8 = 60
And....the angle on the right side of line K = 5(26) - 10 = 130 - 10 = 120
The angle on the right side of line L actually must be 3x + 42 = 3(26) + 42 = 78 + 42 = 120.....which makes sense, because parallel lines intersected by a transversal will have corresonding angles equal
As a check, the angle on the left side of line L should = 60....let's see... (26) + 34 = 60.....yep !!!
And there you are.....
