3^3=3*3*3=9*3=27
$$\left({\frac{{\mathtt{28}}}{{\mathtt{3}}}}\right){\mathtt{\,\times\,}}\left({\frac{{\mathtt{16}}}{{\mathtt{3}}}}\right) = {\frac{{\mathtt{448}}}{{\mathtt{9}}}} = {\mathtt{49.777\: \!777\: \!777\: \!777\: \!777\: \!8}}$$
Admins, if anyone not enrolled in this challenge posts an answer (including anons), will you delete the irrelevant post?
Take the square root of 400 to find x.
That statement is false, 42 is less than l-93l
(l-93l=93)
4 squared=4^2=4*4=16.
Find two numbers that add up to negative five and multiply to -24.
Those numbers are -8 and 3, so x^2-5x-24=(x-8)(x+3)
$${\frac{{\mathtt{1\,114}}}{{\mathtt{4}}}} = {\frac{{\mathtt{557}}}{{\mathtt{2}}}} = {\mathtt{278.5}}$$
