envoy

Thank you for the help, I found the hypotenuse was 5 and found sin L to be 2/5

They are (2, 3); (-3, 2); and (2, -3)

Thank you guys for you help! I appreciate it

Thank you for you help! 

Basically what I did was I made all the inequalities.

I got

3n+2n+15>n+30 --------> n>15/2

3n+n+30> 2n+15 -------> n>15/4

2n+15+n+30>3n (no use)

I had to make a diagram for this next part. 

We know BC>AC because largest side is opposite largest angle, smallest side is opposite smallest angle. We also know AC>AB from similar reasoning. This means

n+30>2n+15 -------> n<15

2n+15>3n ------> n<15

There are 11 values of n that satisfy all of the inequalities

Thank you!