Grammar Fascist

0 Questions
13 Answers

+37

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Stu,

You're all good, man. Just had to get you back. ;P I think we're all still learning...perhaps save Rom. Haha!

Warm Regards,
Grammar Fascist

Grammar Fascist14 Feb 2014

+37

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Stu,

I'm pretty sure the answer is not 5/4. If you plug in 5/4 for x, you'll see that it doesn't work. I'm not sure what you did wrong, but the answer is 5/2. Everything else you said in order to solve it is good, though. I would remind you that when you try to get an x ² to just x by square rooting both sides of the equation, you must make sure to sqrt. both the numerator and denominator if you have a fraction on the other side. I.e. 25/4 = Sqrt(25)/Sqrt.(4).

Just remember, Logan, that the easiest way to solve these simple algebraic equations is to get everything with x attached to it on one side, and everything without x attached to it on the other side. From there, it's just simplifying and simple algebra. Best of luck!

Hope that helps!

Warm Regards,
Grammar Fascist

Grammar Fascist14 Feb 2014

+37

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Ah, I see. I read it wrong all together. My apologies, Chef. Go with what Melody said. ^-^ I have no degree in mathematics. Matter of fact, I'm not even out of high school. Haha, bear with me, you all.

Grammar Fascist14 Feb 2014

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Stu,

He's not asking the same group three different times. Instead, he's asking the same group and it progressively gets smaller as more and more people turn him down. Of the original 60, 1/3 WON'T help him, so 2/3 WILL maybe help him. Of the 2/3 of the original 60 who might help him, 2/5 of that group quickly inform (and I assume that's inform and binform is incorrect.) him that they might help. Of the 2/5 of the 2/3 of the original 60 people, 1/2 WON'T help him, thus, 1/2 WILL help him. So, you end up with: 1/2 of 2/5 of 2/3 of 60--equation form: (1/2)(2/5)(2/3)(60) = number of people who will help. Yes, it is multiplication. Simply because you're narrowing down the same group, not asking the same group three different times. I can't really explain it much better than that. I don't know the exact science (err, math, I guess) behind it, but I know that it's a probability problem and that you multiply fractions in those. Perhaps Rom or Melody could shed some light on the semantics of why you multiply.

Thanks for the high praise, man! That's kind of you; I just like helping people! However, I'm afraid my experience is severely limited compared to some other users here. When it comes to projectiles and LaTex, I'm completely lost. I'll love those to the pros! ;D

Warm Regards,
Grammar Fascist

Grammar Fascist14 Feb 2014

+37

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For the sake of having every question answered....the obvious answer is:

1+1=[(4 ²)/(8*2/2)]

Have a nice day, abc.

Warm Regards,
Grammar Fascist

Grammar Fascist14 Feb 2014

+37

0

Chefboyardeeezie,

I believe this is a problem of probability, which means we have to multiply fractions. We want to get the fractions of every group who might lend him money. So the first group has 2/3 (remember this is about who WILL lend him money, not who WON'T. If 1/3 won't lend, 2/3 will.), the second group has 2/5, and the last group has 1/2. So, writing this out as an equation we get:

(2/3)*(2/5)*(1/2) = 4/30, but we have to simplify down to 2/15.

So, if he asked 60 people, and 2/15 lent him money, some quick math and logic (let me know if you need me to write this last part as an equation, too!) tells us that 8 people out of the 60 lent him money.

Hope that helps!

Warm Regards,
Grammar Fascist

Grammar Fascist14 Feb 2014

+37

+6

Quote:
Rules:
You have to use some or all of the numbers to make the magic number. You are not allowed to use any of the numbers twice. (Unless one was written twice in the first place)
You can use brackets, +, -, x, or divide and that is it.

EASIER ONE
3,2,8,10 and the magic number is 120

HARD ONE
2,5,9,6,4 and the magic number is 536

Here's how I did the easier one: [(3*8*10/2)] = 120

Here's how I did the hard one: [(5*9*6*2) - 4] = 536

Pretty fun stuff! (Good?)

Grammar Fascist14 Feb 2014

+37

+8

Yeah...not even going to try that one. I have other things I must dwell on. Sorry I haven't been able to assist in answering anything today; Tuesdays and Thursdays are especially busy for me. I'll try to help tomorrow, but no promises! I'm a busy man....I do enjoy helping people out, though!

Grammar Fascist14 Feb 2014

+37

+8

I believe I've got it.

You ask either of the brothers how the other brother would tell you to get to Krighontyr from the T crossing. Then you go the opposite direction.

Let's think about it.

Let's say that the correct path is R and you pick the false one to question.

The false brother knows that the true brother would say R, so he would say L, lying about the answer.

If by chance you got the true brother, then he would say L, too because he knows that the false brother would lie about the correct answer.

Either way you get the same answer and know that it's false; you must go the other way to Krighontyr!

This works regardless of what the true path is or who you ask because you'll always end up with a false answer.

That was fun.

Grammar Fascist13 Feb 2014

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What does "In" stand for? Is it a variable? If so, you can't solve the problem because there are two variable and we don't know the value of either. Please clarify on this bit so I can try to help!

Warm Regards,
Grammar Fascist

Grammar Fascist12 Feb 2014

+37

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The first one you got is correct! Trick to simplifying squares is finding perfect squares hidden in there!

You also got the second one right! Good job! If I worked the example you gave me backwards (7 sqrt.11) then I would have to square 7 to get it back to what it would've been (49) and then multiply that number by 11. Thus, we would've gotten sqrt. 49 x sqrt 11 = sqrt 539. So, if you wanted to simplify the sqrt. of 539, you would pull the sqrt. of 49 and the sqrt. of 11 out of it, and then simplify the sqrt. of 49 to 7 and be left with 7sqrt11. See what I'm saying? If not, let me know.

Sqrt of 48x ² can be a bit tricky at first glance, but it is deceptively easy. Think about it. What is the square root of x ²? It's just x! The sqrt. of 48 can be reduced to 4sqrt3 because the sqrt16(sqrt3)=sqrt48 (notice how I plucked the perfect square of 16 out of there?) So, your answer would end up as: 4sqrt3x.

You wouldn't want to include a cubed number in the answer of your simplified sqrt, so the answer for the last one you got is incorrect. What you want to do is look for perfect squares in 96. 16 happens to be one! The sqrt16 x sqrt6 = sqrt96. Simplifying the perfect square, we get 4sqrt.6 for our answer.

Hope that helps! As always, if there is anything still not clear, please feel free to repost your problem, and I'll do my best to help you.

Good luck!

Warm Regards,
Grammar Fascist

Grammar Fascist12 Feb 2014

+37

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Quadratic equations are characterized by this equation: ax ² + bx + c = 0 where a, b, and c are all real numbers not equaling zero. These are called coefficients, quadratic coefficients, to be precise. In order to have a quadratic, you must have something that looks like that equation, or something that can be arranged to look like that equation. If you just have one variable with no powers, then you have a standard algebraic equation. E.g. 2x ² + 4x + 3 = 0 <--quadratic; 2x + 4 = 3x - 1 <-- standard algebraic. Hope that answers your first question--if not, please restate your question again so I can better understand and answer it.

Now, all the equations you listed were standard algebraic equations. I'm not sure how you learned how to solve them, but I always learned to get the numbers with the variables attached to them(x, t, y, etc.) on one side of the equation, and the normal numbers on another. Let's take that first question that you got wrong as an example:

3x+4= 4x+3

First, let's subtract 3x from both sides to get the "x's" on one side. 3x's on the left cancel and we're left with: 4 = x + 3 (Subtract 3x from 4x)

From there, we subtract three from both sides, leaving us with 1 = x...and there you have it! 1 = x. If you plug 1 back in for x, you'll see that it lines up.

We'll do one more, and then I'll let you do the rest by yourself, using this method.

-2(x-3)=-12

First, we want to eliminate any parentheses from the equation. That's pretty much a general rule for algebraic equations. So, multiplying -2 throughout the parentheses, we get: -2x + 6 = -12

Now, let's subtract 6 from both sides to get the number with x attached to it by itself. We end up with: -2x = -18

From here, we divide both sides by - 2 to get x = ___ Working it out, we find that x = 9 (-18/-2 = 9 [two negatives cancel, leaving us with a positive])

Thus, x = 9. Once again, you will find that the answer works with 9 as x.

So, if you identify your equation as a standard algebraic equation, then go ahead and try to get all the numbers with variables attached on one side and the numbers without variables on the other. From there, it's pretty easy to solve for your lone variable. Hope that helps! I suggest you try this out a couple of times to get the hang of it. If it doesn't work, just repost and I"ll try to help you further!

Best of luck in you algebraic pursuits!

Warm Regards,
Grammar Fascist

Grammar Fascist12 Feb 2014

+37

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'Twas an honest mistake! I tried to do a smiley, but I'm afraid that my inexperience prompted an unsavory display of my internet prowess, or lack thereof.

Grammar Fascist12 Feb 2014