ItzCubez

\(\big(\frac{2}{3}*\frac{2}{3}\big) + 6.25\)

\(\frac{4}{9}+6.25\)

\(\frac{4}{9}+6\frac{1}{4}\)

\(\frac{16}{36}+6\frac{9}{36}\)

\(6\frac{25}{36}\)

\(-3+(-2) \)

\(=\boxed{-5}\)

Inequalities:Example 1:      Latex code: x+1 \geqslant 0

                   Example 2:      Latex code: x-1 \leqslant 0

Instead of \geqslant and \leqslant you can use

\(x+1\geq0 \)Latex code: x+1\geq0

\(x-1\leq0\)Latex code: x-1\leq0

That is a very good point. The equation is not "unsolvable" (I just did it) but there is \(\boxed{\text{No Solution}}\)

c=-25

\(13=-\frac{x}{2}\)

\(26=-x\)

\(x=-26\)

Density (p) = \(\frac{Mass (m)}{Volume (V)}\)

Can you take it from here?

Let's start by simplifying this nasty inequality.

\(3x+11>6x+8\)

\((3x-6x)+(11-11)>(6x-6x)+(8-11)\)

\(-3x>-3\) {nl}  

There is something very important here, there is a rule, that when you multiply an inequality by a negative number (we are doing this to get rid of the negative signs) you "flip" the inequality sign.

\((-3x)(-1)>(-3)(-1)\)

\(3x<3\)

\(\frac{3x}{3}<\frac{3}{3}\)

\(x<1\)

\(\frac{3}{4}-\frac{1}{16}\)

OK, you have these two fractions. Now we find the Least Common Denominator (LCD) which in this case is 16. To produce an equilivant faction with a denominator of 16, we need to change the numerator in proportion to the denominator. To produce 16 from 4, we need to multiply by 4 (4*4=16) so we multiply the top numeber as well.

\((\frac{3}{4}*\frac{4}{4})-\frac{1}{16}\)

\(\frac{12}{16}-\frac{1}{16}\)

Ah! Now we have something we can easily work with.

\(\boxed{\frac{11}{16}}\)

We make sure that this fraction can't be simplified any further without making sub-fractions and decimals in fractions. It can't; therefore, this must be the answer.

I'm not sure by what you mean by, "if i had to buy 4100 brochures for .40 how much would it cost."

Do you mean the individual costs, or the cost of buying 4100 brochures for .40?

Well, this is a type of geometric probability. 

Simplifying

x3 + -10x + 9 = 0

Reorder the terms:

9 + -10x + x3 = 0

Solving 9 + -10x + x3 = 0

Solving for variable 'x'. The solution to this equation could not be determined.

Well according the order of operations, multiplication or division (left to right), then addition or subtraction (left to right).

I am assuming you mean this:

\(3*5-1*10\)

We have the multiplication, you start with that.

\(15 - 10\)

Then we have a simple subtraction problem

\(\boxed{5}\)

Hope this helped!

Yes, that is right. 

\(\frac{3}{4} (x)+1=\frac{3}{4}(x)-7 \)

\(\frac{3x}{4}+1=\frac{3x}{4}-7\)

\((\frac{3x}{4}-\frac{3x}{4})+1=(\frac{3x}{4}-\frac{3x}{4})-7\)

\(1=-7\)

This an AoPS Homework Question. This can be done entirely by casework.

If done correctly, you should have 105+78+55+36+21+10+3=308

Here is a gigantic hint from AoPS Wiki (http://artofproblemsolving.com/wiki/index.php?title=Committee_forming)