So, the correct answer is 24.
Thanks @CPhill.
Okay, thanks.
\({x}^{2}+4x+3=-(2x+5)\)
\({x}^{2}+4x+3=-2x-5\)
\({x}^{2}+4x+3+5=-2x-5+5\)
\({x}^{2}+4x+8=-2x \)
\(x^2+4x+8+2x=-2x+2x\)
\(x^2+6x+8=0\)
\(x_{1,\:2}=\frac{-6\pm \sqrt{6^2-4\cdot \:1\cdot \:8}}{2\cdot \:1}\)
\(\sqrt{6^2-4\cdot \:1\cdot \:8}=2 \)
\(x_{1,\:2}=\frac{-6\pm \:2}{2\cdot \:1}\)
\(x_1=\frac{-6+2}{2\cdot \:1},\:x_2=\frac{-6-2}{2\cdot \:1}\)
x=-2
x=-4
X can be -2 or -4
There are 2 solutions to X.
What do you want us to solve? Should we solve for x?
CPhill is beating me to everything. :)
I think X=1.
\(\frac{a+b}{a}=x\)
\(\frac{a+b}{a}a=xa\) (I multiplied both sides by A.) Simplify and it turns into a+b=xa
A+B-B=XA-B (I subtracted B from both sides)
A=XA-B
A-XA=XA-B-XA (I subtracted XA from both sides)
a-xa=-b a(1-x)=-b
\(\frac{a\left(1-x\right)}{1-x}=\frac{-b}{1-x};\)
So, x=1. I hope this helps.
Understood, sorry.
(88, 85, 82, 79, 76, 73, 70, 67, 64, 61, 58, 55, 52, 49, 46, 43, 40, 37, 34, 31, 28, 25, 22, 19, 16, 13, 10, 7, 4, 1, -2, -5, -8, -11, -14, -17)
So 35 terms appear BEFORE -17.
30%=12 Pictures
30/3=10% 12/3=4 Pictures
10%=4 Pictures
10*10=100% 4*10=40 Pictures So, the photographer took 40 pictures.
Y=3 X=-3 3+(-3)=0 9+(-18)=-9
I don't agree. This does not fit the question requirements.
Nice job CPhill.
And you don't get the same amount as the initial pay. I will give an example.
Let's say you have $100 monthly.
30% more means $130 monthly. Then 30% less is not $100 monthly. 30% of 130 is 39.
130-39=91.
So you don't get the same amount of pay.
You should be able to take it from here.
I don't understand this problem. Is this a yes or no question???
So, the correct answer is 24.