Melody

921 Questions
34315 Answers

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Mathigon website

I just discovered a site called mathigon

https://mathigon.org/dashboard
और पढ़ें ..

Melody 2 Apr 2022

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Reporting problems.

There are a number of people having problems at the moment.
If you lodge an error can you please give all relevant information that you can think of.
Where you are in the world - the city or the country - is often very important information. और पढ़ें ..

Melody 16 Mar 2022

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How to make an empty rectangle in Latex

I just worked out how to make an empty box of various horizonal size easily in LaTex.
This is not a recommended method, but other methods that I have tried here have not worked.
This coding is really simple. Just put letters inside और पढ़ें ..

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Melody 15 Mar 2022

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856

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HAPPY ANNIVERSARY CHRIS! (CPhill)

I just realized that you became a member here exactly 8 years ago today!

It has been great to have you here all that time

और पढ़ें ..

विषय से परेे

Melody 13 Mar 2022

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WELCOME BACK CPHILL !

Melody 11 Feb 2022

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Very interesting question. No high level maths required.

This question was posted a couple of days ago.
https://web2.0calc.com/questions/geometry_73561

I think it is really interesting. It looks much more difficult than it really needs to be. और पढ़ें ..

Melody 1 Feb 2022

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Members have a better experience. Their questions get more attention.

Almost everyone is posting as a guest.
If you post as a member your questions will have a far greater chance of a timely and helpful response.
If you are a genuine learner and interact with us, you will become known and answerers will do और पढ़ें ..

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Melody 9 Jan 2022

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HAPPY BIRTHDAY CHRIS!

और पढ़ें ..

Melody 20 Des 2021

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Some guidelines for question askers.

Please note:
1) Ask only one question per post.
2) When asking a question talk about what you have tried for yourself. Then people will take you more seriously and will be more able and willing to help.
3) If you get an answer और पढ़ें ..

विषय से परेे

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Melody 4 Nov 2021

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Remeniscing - a little historical humour.

I just found this old post that some of you, who have been around for a while, might find amusing.

https://web2.0calc.com/questions/look-at-the-new-leader-board

विषय से परेे

Melody 29 Okt 2021

+118687

+1

You have to add up the 4 lengths and then divide by 4 to get the average.

Melody29 Sep 2013

+118687

+1

I think this question is in italian, I put it through a translator and this is what I got.

A trapezoid rectangle has the smaller base, the height and the oblique side respectively 9cm long, 4cm 5cm.sapendo cha and the projection of the oblique side on the basis mangiore is 3cm long, determine the extent of the perimeter

Unfortunately, I still don't understand the question. sorry.

Melody29 Sep 2013

+118687

+1

I have no idea what your question means.
Can you explain yourself better?

Melody29 Sep 2013

+118687

+1

With your fingers.

Melody29 Sep 2013

+118687

+1

You could do it on your calculator if you have a fraction button.
otherwise

27 1/4 - 12 8/9
= 27 + 1/4 - (12 + 8/9)
= 27 + 1/4 - 12 - 8/9
= 27 - 12 + 1/4 - 8/9
= 15 +1/4 - 8/9

hopefully you will recognise that 1/4 is less than a half and 8/9 is more than a half. The first one needs to be the biggest unless you want to deal with negative numbers.
So I suggest you change 15 + 1/4 into 14 + 1 + 1/4 and, 1 and a quarter is 5 quarters.
so

=14 + 5/4 - 8/9
Now, you cannot add or subtract fractions unless the denominators (bottoms) are the same. You must find a number that 4 goes into and 9 goes into. 4*9 will work and in this case it is the smallest one.
So you will have to change it to 14 + something over 36 - something else of 36

and I am going to let you finish by yourself.
Happy puzzling.

Melody29 Sep 2013

+118687

+1

How much does an atom of iron weigh? I guess you could google this just as easily as I could. Cheers.

Melody29 Sep 2013

+118687

+1

Just convert the km to metres and do the division on your calculator. The units cancel out. the answer will just be a number.
or
You could convert the metres to km and do the division. The answer will be the same.

Melody29 Sep 2013

+118687

+1

The probability of getting at least one heart is the compliment of getting no hearts.
What I mean is, you either get a heart or you don't so the sum of these 2 probabilities is 1.
All probabilities are between 0 and 1 (0 = can't happen) (1 = must happen)

The probability that the first chosen is not a heart is 48/52
now there are only 51 cards left and only 47 of them are not hearts so
The probability that the second chosen is not a heart is 47/51 etc
So
The probability that none are hearts is

P(no hearts) = 1 - [ 48/52 * 47/51 * 46/50 * 45/49 ]

I hope that you LEARN from my answer.

Melody29 Sep 2013

+118687

+5

Firstly what is bidmas? Do you mean BODMAS ? If you mean bidmas please tell me what the i stands for?

BODMAS stands for
Brackets then
of (as in power of) then
division and multiplication equally important just work left to right then
addition and subtraction equally important just work left to right

Your first question is so easy that I am sure you can do it yourself. Just try putting the brackets in different places until it works.

The second one is a bit tricky. What i will tell you is that it is not 4 squared. There is only one place that you can put the first brackets to change this. There will be 2 sets of brackets altogether.

good luck. Happy puzzling

Melody29 Sep 2013

+118687

+1

Without any brackets this expression is really

=35000 * x^2 - (x / 200) * x
=35000* x^2 - x^2 / 200
=x^2 * (35000 - (1/200))
=34999.995 * x^2

Melody29 Sep 2013