MobiusLoops

3*6*27*4*81*2 = 314928

9y = 314928

Divide both sides by 9. 

(9y) / 9 = 314928 / 9

y = 34992

It is just the least common multiple (LCM) you are looking for!

Let's check 10 first. 10 x 1 = 10. And this isn't divisible by 4 to make a whole number. 

So let's check the next one for 10! 10 x 2 = 20. This IS divisible by 4 to make a whole number! 20 / 4 = 5!

So Mary sold 5 boxes of cookies to get to $20 and Henry sold 2 boxes of cookies to get to $20!

$20 is the answer!

You need 6 1/6's of a pound to make a pound.

1/5 oz of butter = 1/6 lb of jello

To get to a pound of jello, you need to multiply 1/6 by 6 (1/6 x 6) to get to one.

But remember, what you do to one side of the equation, you also have to do to the other.

1/5 oz * 6 = 1/6 lb * 6

1/5 oz * 6 = 1 lb of Jello

6/5 ounces of butter = 1 lb of Jello

So you need 6/5 ounces of butter to make 1 pound of Jello! 

Thanks Alan! This really helped :)

The graph you showed was the graph of g(t), right? From what I can see, the turning points are at -1.5 and 2? So does that mean the set is \((-\infty, \frac{-3}{2}) \cup (2, \infty)\)?

Given info: {} = r

Problem: 6r - 8 = 8 + 6r

Plugging in {} for r gives us: 6{} - 8 = 8 + 6{}

Remove 6{} from each side: 6{} - 8 - 6{} = 8 + 6{} - 6{}

Simplify: -8 = 8

This is not possible, so there are NO SOLUTIONS

Problem in the title: 52 x 440 = 22880

Problem you asked: 520 x 440 = 228800

The function is always increasing, right? So does that mean the solution would be \((0, \frac{\pi}{2})\cup(\frac{\pi}{2}, \frac{3\pi}{2})\cup(\frac{3\pi}{2}, 2\pi)\)?

Boolean Algebra is the algebra of two values, 0 and 1. Keep in mind that these values don't work like the actual numbers (ex. 1+1=2). It is useful for computers and electronics that are based on the binary system. I don't really understand how to "do" Boolean Algebra, but it is useful for understanding larger concepts. There are quite a few good videos on this subject, so they can explain it better than I can.

Also, search up videos on "logic gates" because it is very helpful when learning this subject :)

I mean you could go with him and play Minecraft while waiting :)

I know this is a troll question, but here you go :)

I am guessing a lot of stuff since you didn't put them in (work distance, etc.) Also, the answer will be a rough estimate in years.

35, 757, 093 minutes to get to the store-----> roughly 697.01 years

Since your father is slow in the head, it will take him about 5 minutes to realize he doesn't have enough money to buy the milk. Going to

work, guessing about 30 miles from the store in the opposite direction of your house, it takes him, with the given 0.05 mph, about 600 hours or 0.07 years, to get to his work.

That is if, and only if, a cop does not pull over your father for the 200th time for diving immensely slow. It would be a usual sentence of fewer than 30 days. However, your father has been there a lot and the judge has had enough of your father being a public nuisance. This makes the judge sentence your father to jail time for 50 years. Worst-case scenario, your father is sentenced to a lifetime jail residence so make that infinite years.

However, let's not think that way. He gets to work and has to work for the listed 950, 000 days (roughly 2666.67 years). Getting back to the store will take another 0.07 years, buying the milk will take about 50 more years with the state your father's mind is in. Finally, it will take another 697.01 years to get home. 

Totaled up, this is an approximate 4160.83 years for your father to come back home with the milk. Unfortunately, the milk is spoiled by the time he gets home, unless it's the special "Never Go Bad Milk" brand, which is probably not the case since your father probably read the label wrong and got the "Goes Bad in 3 Seconds Milk" brand instead. Thus repeating the never-ending cycle.

Ohhhh. This makes sense! I don't really remember how to solve these problems because I missed one class on this topic and didn't fully understand it. Thanks alot!

Might as well make this easier for others to read.

Suppose that \(\frac{\log_3 2}{\log_2 9} \cdot \frac{\log_3 4}{\log_2 27} \cdot \frac{\log_3 8}{\log_2 81} \cdots \frac{\log_3 2^{100}}{\log_2 3^{101}} = \frac{(\log_3 2)^m}{n}\), where m and n are integers. Find m+n.

Thanks for the explanation!

Thanks for posting the "solution" without an explanation! But it would be nice if you showed me how you solved it :)

YAY CPhill!