Tacoflea

we can use substitution such that for the first equation, we can rearrange it to solve for

b: a + ab = 250

ab = 250 - a

b = (250 - a) / a

Substituting this expression for "b" into the second equation, we get:

a - ab = -240

a - a(250 - a)/a = -240

a - (250 - a) = -240

2a - 250 = -240

2a = 10

a = 5

if you need to find b, substitute a into one of the equations and simplify the equation.

Lets rearrange the expression such that

(2x + 10)^4 * (x + 5)^4 = [(2(x + 5))^4 * (x + 5)^4]

Now, we can use the difference of squares identity by letting a = 2(x + 5) and b = x + 5, which gives us:

[(2(x + 5))^4 * (x + 5)^4] = [(2(x + 5))^2 * (x + 5)^2]^2 = [(4(x + 5)^2) * (x + 5)^2]^2 = [4(x + 5)^4]^2 = 16(x + 5)^8

 the simplified expression is 16(x + 5)^8.

To calculate the square root of 7! where n! stands for n*(n-1)(n-2)...2*1, we can use the factorial property:

7! = 7654321

sqrt(7!) = sqrt(7654321) = sqrt(7) * sqrt(6) * sqrt(5) * sqrt(4) * sqrt(3) * sqrt(2) * sqrt(1)

sqrt(7) * sqrt(6) * sqrt(5) * sqrt(4) * sqrt(3) * sqrt(2) * sqrt(1) = 7^(1/2) * 6^(1/2) * 5^(1/2) * 4^(1/2) * 3^(1/2) * 2^(1/2) * 1

Using this information to jumpstart your question, try simplifying the last expression.