whoisjoe

He has to draw arcs through both points and then arcs that stem from those arcs created in the first step.

if you need help with constructions try going here:

https://mathopenref.com/tocs/constructionstoc.html

The line she constructed is not passing through C....

For styling purposes:

\(\pm(1+i), \pm(1-i)\)

Try Drawing a Venn Diagram!

This is just 3 to the 3rd power, or \(3^3\), which is also known as 27.

This is just 3 to the 4th power, or \(3^4\), which is also known as 81.

Whoops! I meant 3^4 power, which is 81.

This is the answer assuming the first case I stated (2 different terms being multiplied)

\(\frac{\left(x^2+x-12\right)\left(3x^2+11x-4\right)}{\left(x-2\right)\left(x^2-4\right)}\)

Are you saying that (x ^ 2 + x - 12)/(x - 2)  is getting multiplied by (3x ^ 2 + 11x - 4)/(x ^ 2 - 4) as 2 seperate terms, like (x ^ 2 + x - 12)/(x - 2) *  (3x ^ 2 + 11x - 4)/(x ^ 2 - 4), or is  (3x ^ 2 + 11x - 4)/(x ^ 2 - 4) in the denominator of (x ^ 2 + x - 12)/(x - 2)? Try using LaTeX to make the problem clearer.

Hmm. We seem to be disagreeing. I think you forgot that y = 2 + 5/6x is a different term than 4x-3y=3, lol. Guest probably should have put something to tell us that they are 2 different terms, unless I am the mistaken one. Oh I see you didn't see that it was a system of equations so you just solved for x!

As for the 5/6x confusion you are having, just put the 5/6x in the term you are substituting in for "y", like I did when I said \(\mathrm{Subsititute\:}y=2+\frac{5}{6}\cdot \:x\)