In the problem it said
Let F(x) be the real-valued function defined for all real x except for x=1 and x=2
turn this into: 7x^2 + 8x - h = 0
using the quadratic formula to find the solutions:\({-8 \pm \sqrt{64+28h} \over 14}\)
this means that \(\sqrt{64+28h}\) = 0
h = \(-\)\(16\over 7\)
The ratio can be expressed as 9x:2x:5x. we get the equation:
\(9x*2+2x*5+5x*10-9*\frac{4}{9}x*2-50=300\)
Simplifying it we get:
\(18x+10x+50x-8x=350\)
\(70x=350\)
Soving it we get x=5. This means that there are \(5*5=\boxed{25}\) $10 notes
a=3 b=2
you can see the answer here: https://web2.0calc.com/questions/how-many-ways-are-there-to-put-4-balls-in-3-boxes_2
read the one with the most thumbs ups
the total of the 10 numbers is: 10(85)=850
subtracting 70 and 78 gives 850-70-78=702
dividing by 8 gives: 87.75
since there are 9 numbers and choose 3 to be in so we can do 9!/6!=504 but some numbers are repeated in the list which are 5 and 6. 5 is repeated three times and 6 is reapeated twice so we divide by 2! and 3!
504/2/6=42
100^2-100+201=10101
101^2-101+201=10301
10301 is prime so the gcd is 1
for \(\LaTeX\)you can't copy and paste you have to type it in your self
G+16=24-3/4*G
G=8-3/4*G
7/4*G=8
G=(32)/7
The one on this website or a different one? For web2.0calc just do (numerator÷denominator) i think
x+y=13
2x+6y=50
x+3y=25
subsitution gives:
2y=12
y=6 x=7
