+676 To answer this question you will need to break down this equation.
First of all lets try and simplify all that can be simplified.
1x+xx+2=1
First of all we can see a fraction that can be simplified. That is ofcourse, X Over X. Any number, if the Numerator and Denominator is identical, then it will always equal to 1. So being that, we will substitute X over X with 1.
1x+1+2=1
Let us move over some numbers across the = sign.
1x=1−2−1
Lets solve that:
1x=−2
Now we must eradicate the denominator. To do that we will multiply both sides by x.
1x×x=−(2×x)
Lets solve that!
1x×x=−(2×x)⇒x=−12⇒x=−0.5
We have jumped a step, however, you should be able to see what has been done.
x=-0.5
Lets substitute that in!
1−0.5+(−0.5)−0.5+2=1
Lets solve it now and see if it work!
1−0.5=−2
(−0.5)−0.5=1
−2+1+2=1
Is it correct?
Yes!
Therefore x=−0.5
+676 To answer this question you will need to break down this equation.
First of all lets try and simplify all that can be simplified.
1x+xx+2=1
First of all we can see a fraction that can be simplified. That is ofcourse, X Over X. Any number, if the Numerator and Denominator is identical, then it will always equal to 1. So being that, we will substitute X over X with 1.
1x+1+2=1
Let us move over some numbers across the = sign.
1x=1−2−1
Lets solve that:
1x=−2
Now we must eradicate the denominator. To do that we will multiply both sides by x.
1x×x=−(2×x)
Lets solve that!
1x×x=−(2×x)⇒x=−12⇒x=−0.5
We have jumped a step, however, you should be able to see what has been done.
x=-0.5
Lets substitute that in!
1−0.5+(−0.5)−0.5+2=1
Lets solve it now and see if it work!
1−0.5=−2
(−0.5)−0.5=1
−2+1+2=1
Is it correct?
Yes!
Therefore x=−0.5
