$$\begin{array}{rlll}
\frac{2x}{4\pi}+\frac{1-x}{2}&=&0\\\\
\frac{x}{2\pi}+\frac{1-x}{2}&=&0\\\\
2\pi \times \left(\frac{x}{2\pi}+\frac{1-x}{2}\right)&=&2\pi\times 0\\\\
x+\pi(1-x)&=&0\\\\
x+\pi-\pi x &=&0\\\\
x(1-\pi )+\pi &=&0\\\\
x(1-\pi )&=&-\pi \\\\
x&=&\frac{-\pi}{(1-\pi )} \\\\
x&=&\frac{\pi}{(\pi-1 )} \\\\
\end{array}$$
$$\begin{array}{rlll}
\frac{2x}{4\pi}+\frac{1-x}{2}&=&0\\\\
\frac{x}{2\pi}+\frac{1-x}{2}&=&0\\\\
2\pi \times \left(\frac{x}{2\pi}+\frac{1-x}{2}\right)&=&2\pi\times 0\\\\
x+\pi(1-x)&=&0\\\\
x+\pi-\pi x &=&0\\\\
x(1-\pi )+\pi &=&0\\\\
x(1-\pi )&=&-\pi \\\\
x&=&\frac{-\pi}{(1-\pi )} \\\\
x&=&\frac{\pi}{(\pi-1 )} \\\\
\end{array}$$