4+12+36+...;n=15
The sum is 2∗(3n−1)
If n=15 the sum is 2∗(315−1)=28697812
I believe you have a geometric series here, and you would like to find the 15th term ??
The terms of the series are given by 4*3(n-1)
so, we have 4*3(15-1) = 4*3(14) = 19,131,876
Sorry....Anonymous is correct......I forgot that we were finding a sum !! My bad !!
Thumbs down for me, and Thumbs up for Anonymous.....
Thank you Chris