8x^2+12x+1=0 uses the quadratic formula to solve for roots.

This will help you remember it!

https://www.youtube.com/watch?v=O8ezDEk3qCg

8x^2+12x+1=0

$${\mathtt{8}}{\mathtt{\,\times\,}}{{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{\,-\,}}{\frac{\left({\sqrt{{\mathtt{7}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{3}}\right)}{{\mathtt{4}}}}\\ {\mathtt{x}} = {\frac{\left({\sqrt{{\mathtt{7}}}}{\mathtt{\,-\,}}{\mathtt{3}}\right)}{{\mathtt{4}}}}\\ \end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = -{\mathtt{1.411\: \!437\: \!827\: \!766\: \!147\: \!6}}\\ {\mathtt{x}} = -{\mathtt{0.088\: \!562\: \!172\: \!233\: \!852\: \!4}}\\ \end{array} \right\}$$