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(Abc)^43/(bc)^3*b^3/27a^5

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(A*b*c)^4*3/(b*c)^3*b^3/27a^5

math algebra

Guest Aug 24, 2014

Best Answer

+130466

+5

(A*b*c)^4*3/(b*c)^3*b^3/27a^5 So we have, taking it in steps.......

[A⁴b⁴c⁴]*[3] /[b³c³] = 3[A⁴bc]

3[A⁴bc]*[b³] = 3[A⁴b⁴c]

3[A⁴b⁴c] / [27a⁵ ] =

[A⁴b⁴c] / [9a⁵ ]

CPhill Aug 24, 2014

1⁺⁰ Answers

+130466

+5

Best Answer

(A*b*c)^4*3/(b*c)^3*b^3/27a^5 So we have, taking it in steps.......

[A⁴b⁴c⁴]*[3] /[b³c³] = 3[A⁴bc]

3[A⁴bc]*[b³] = 3[A⁴b⁴c]

3[A⁴b⁴c] / [27a⁵ ] =

[A⁴b⁴c] / [9a⁵ ]

CPhill Aug 24, 2014

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