Let a and b be the solutions to 5x^2 - 11x + 4 = 4x^2 + 11x + 13. Find \frac{1}{a^3} + \frac{1}{b^3}.
Let a and b be the solutions to 5x2−11x+4=4x2+11x+13. Find 1a3+1b3.
For this question, I'm just going to solve for a and b, since it is not that hard.
You can use the quadratic formula, which is −b+or−√b2−4ac2a. The +or- just stands for plus or minus. Any moderators tell me what the symbol for that is? I kind of forgot. Anyways, by plugging in the formula to the equation, first we got to simplify it.
5x2−11x+4=4x2+11x+13
x2−22x−9=0
x=√130+11,−√130+11
You can take it from here.
PS: I think you made a mistake, this answer looks kinda weird. Maybe it wasn't +11x it was -11x, so it would be a perfect square and easier to solve.