The temperture of some water with a mass of 10.0g and a specific heat of 4.2 changed form 25.0 degrees celcius to 35 degrees celcius.how much heat was absorbed?
The units of specific heat are important. You didn't specify them, but for water the specific heat is 4.2 J/(g.K). So the heat absorbed is 10*4.2*(35-25) J = 420 Joules.
The units of specific heat are important. You didn't specify them, but for water the specific heat is 4.2 J/(g.K). So the heat absorbed is 10*4.2*(35-25) J = 420 Joules.
+3502 
