Considering the Fibonacci sequence how does F with subscript 1+2+3+4+5 = 610?
F(1+2+3+4+5) = F(15) = 610
BTW.......we can calculate any Fibonacci number with index "n" using this formula....
[Phin - (-Phi)-n ] / √5 ....where Phi = [ 1 + √5 ] / 2
The odd thing about this "formula" is that it looks as though it should produce some irrational number........but it doesn't !!!!
Try the formula with n = 15 and see if it doesn't give you 610.......
F(1+2+3+4+5) = F(15) = 610
BTW.......we can calculate any Fibonacci number with index "n" using this formula....
[Phin - (-Phi)-n ] / √5 ....where Phi = [ 1 + √5 ] / 2
The odd thing about this "formula" is that it looks as though it should produce some irrational number........but it doesn't !!!!
Try the formula with n = 15 and see if it doesn't give you 610.......