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Factor x^8 - y^8 as the product of four polynomials of degree 1, each of which has a positive coefficient of x.

 Jun 22, 2021
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x8y8=(x4)2(y4)2=(x4y4)(x4+y4)=((x2)2(y2)2)(x4+y4)=(x2y2)(x2+y2)(x4+y4)=(xy)(x+y)(x2+y2)(x4+y4)

Can you take it from here?

Hint: Manipulate $x^2 + y^2$ into $(x+y)^2 - 2xy$ and do the same thing with $x^4 + y^4.$ You can substitute your equation for $x^2 + y^2$ and do some further manipulation and you are done. If you have degrees $>1,$ you can square root it.

 Jun 22, 2021

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