Find the derivative of f(x) = 5x^2 -6x +4

Find the derivative of

$f(x)=5x^{2}-6x+4$

$f'(x)= 10x -6$

Find the derivative of

$f(x)=\frac{8}{x^{7} }$

$f(x)= 8\times x^{-7}$

$f'(x)=8\times x^{-8 } \times -7$ 

$f'(x)=-56x^{-8}$

$y = 5x^2 - 6x + 4\\ y' = 5\times 2 \times x^{2-1}-6\times 1 \times x^{1-1}+4\times 0 \times x^{0-1}=10x - 6$

$y = \dfrac{8}{x^7}\\ y'=8 \dfrac{d}{dx}x^{-7}=(8)(-7)(x^{-7-1})=-56x^{-8}=-\dfrac{56}{x^8}$

Same as asinus's answer.