+971 In the diagram, $ABCD$ is a square. Find $PR.$
The side length of the square is 10. L, M, N, O are midpoints.
+29 Start out by drawing out your answer on graph paper.
Point A is at (0,0), Point B is at (10,0), Point C is at (10,10) Point D is at (0,10).
Then you can draw each of the lines. The equations for each of the lines are: DL: y = -2x + 10, NB: y = -2x + 20, OC: y = 1/2x + 5, and AM: y = 1/2x.
After drawing out all of the lines, you can find that Point R is at (6,8) and point P is at (4,2).
Use the distance formula or pythag to find the length between the two points.
\(\sqrt{2^2+6^2}=\sqrt{40}=2\sqrt10\)
Answer: \(2\sqrt10\)
+29 Start out by drawing out your answer on graph paper.
Point A is at (0,0), Point B is at (10,0), Point C is at (10,10) Point D is at (0,10).
Then you can draw each of the lines. The equations for each of the lines are: DL: y = -2x + 10, NB: y = -2x + 20, OC: y = 1/2x + 5, and AM: y = 1/2x.
After drawing out all of the lines, you can find that Point R is at (6,8) and point P is at (4,2).
Use the distance formula or pythag to find the length between the two points.
\(\sqrt{2^2+6^2}=\sqrt{40}=2\sqrt10\)
Answer: \(2\sqrt10\)
