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There are three real numbers $x$ that are not in the domain of $f(x) = \frac{1}{1+\frac{1}{1+\frac 1x}}.$ What is the sum of those three numbers?

Guest Jul 19, 2021

edited by Guest Jul 19, 2021

MathProblemSolver101 · Answer 1 · 2021-07-19T07:06:38

X = 0

1+1/x=0

x+1=0

x=-1

1+1/(1+1/x) = 0

1 + 1/x + 1 = 0

2+ 1/x = 0

2x +1 = 0

2x = -1

x = -1/2

0+(-1)+(-1/2)=-3/2