HELP!!!!

Solve for x:
(-2-x)/8+(x-3)/6+x/3 = (3 x-1)/6

Put each term in (-2-x)/8+(x-3)/6+x/3 over the common denominator 24: (-2-x)/8+(x-3)/6+x/3 = (3 (-2-x))/24+(4 (x-3))/24+(8 x)/24:
(3 (-2-x))/24+(4 (x-3))/24+(8 x)/24 = (3 x-1)/6

(3 (-2-x))/24+(4 (x-3))/24+(8 x)/24 = (3 (-2-x)+4 (x-3)+8 x)/24:
(3 (-2-x)+4 (x-3)+8 x)/24 = (3 x-1)/6

3 (-2-x) = -6-3 x:
(-6-3 x+4 (x-3)+8 x)/24 = (3 x-1)/6

4 (x-3) = 4 x-12:
(4 x-12+8 x-3 x-6)/24 = (3 x-1)/6

Grouping like terms, 8 x+4 x-3 x-12-6 = (-3 x+4 x+8 x)+(-6-12):
((-3 x+4 x+8 x)+(-6-12))/24 = (3 x-1)/6

-3 x+4 x+8 x = 9 x:
(9 x+(-6-12))/24 = (3 x-1)/6

-6-12 = -18:
(9 x+-18)/24 = (3 x-1)/6

Multiply both sides by 24:
(24 (9 x-18))/24 = 4 (3 x-1)

(24 (9 x-18))/24 = 24/24×(9 x-18) = 9 x-18:
9 x-18 = (24 (3 x-1))/6

24/6 = (6×4)/6 = 4:
9 x-18 = 4 (3 x-1)

Expand out terms of the right hand side:
9 x-18 = 12 x-4

Subtract 12 x from both sides:
(9 x-12 x)-18 = (12 x-12 x)-4

9 x-12 x = -3 x:
-3 x-18 = (12 x-12 x)-4

12 x-12 x = 0:
-3 x-18 = -4

Add 18 to both sides:
(18-18)-3 x = 18-4

18-18 = 0:
-3 x = 18-4

18-4 = 14:
-3 x = 14

Divide both sides of -3 x = 14 by -3:
(-3 x)/(-3) = 14/(-3)

(-3)/(-3) = 1:
x = 14/(-3)

Multiply numerator and denominator of 14/(-3) by -1:
Answer: |x = (-14)/3

How do you solve this problem x/3 - (3-x)/6 - (x+2)/8 = (3x-1)/6 ?

$\frac{x}{3}-\frac{3-x}{6}-\frac{x+2}{8}=\frac{3x-1}{6}$  

                                           $Common \ denominator = 24$

$\frac{x\times 8-4\times (3-x)-3\times (x+2)}{24} =\frac{4\times (3x-1)}{24}$

$8x-12+4x-3x-6=12x-4$

$-3x=14$

${\color{blue}x=-\frac{14}{3}}$

${\color{blue}x=- 4 \frac{2}{3}}$

${\color{blue}x=-4.666\overline{6}}$      !