how dose (3)^2*-3^5/3^4 = -27
$$\\(3)^2*-3^5/3^4\\\\ =\frac{(3)^2*-3^5}{3^4}\\\\ =\frac{9*-3^5}{3^4}\\\\ =9*-1*3^{5-4}\\\\ =9*-1*3\\\\ =-27\\\\$$