i am so lost :(

from equation 1 we get b = 14-a

substituting that into the second equation we get a^3+(14-a)^3=812

now you can try to expand it out, if you need help just ask

So a^3 + b^3 = (a + b)(a^2 - ab + b^2). 

Substituting in, we have 812 = 14(a^2 - ab + b^2).

Simplifying we have 58 = a^2 - ab + b^2.

a^2 - ab + b^2 = (a + b)(a + b) - 3ab. 

Substituting in, we have 58 = (14)(14) - 3ab.

Now we have ab = 46.

Then we also have a^2 - ab + b^2 = (a - b)(a - b) + ab.

Thus, 58 = (a - b)^2 + 46.

(a - b)^2 = 12.

$a - b = \pm{2\sqrt{3}}$

Now we can sove for a. If we add the two equations together, we get 2a = 14 + 2sqrt(3)

Thus, $a = 7 + \sqrt{3}$, and $a = 7 - \sqrt{3}$.

Substituting in, we have $b = 7 - \sqrt{3}$, and $b = 7 - 3\sqrt{3}$.

Thus, our possible for solutions $(a, b)$are:

$(7 + \sqrt{3}, 7 - \sqrt{3})$

$(7 - \sqrt{3}, 7 - 3\sqrt{3})$

omg thank you so much!!