If f ( x) = 2x^2 + 1 and g ( x) = x2 – 7, find ( f + g ) ( x). 3x^2+8 x^2-6 3x^2-6 x^2+8
(f+g)(x) just equals f(x) + g(x)
2x^2 +1 + x^2-7
3x^2 -6
+36916 
