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Let P(x) be a nonconstant polynomial, where all the coefficients are nonnegative integers. Prove that there exist infinitely many positive integers n such that P(n) is composite.

Hint(s):

Remember that if a and b are distinct integers, then P(a) - P(b) is divisible by a - b.

 Jun 27, 2021
 #1
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The simplest polynomial is ax2+bx+c

Let x=kc for kZ

We have ax2+bx+c=a(kc)2+b(kc)+c=ak2c2+bkc+c=c(ak2c+bk+1)

Because there is are at least two factors for ax2+bx+c, P(x) is composite.

 Jun 27, 2021
 #2
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+1

hello person is there another way you could have figured that out?

halpp  Jun 27, 2021

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