Hi guys,
could someone please show a step by step computation for the first and second partial derivation of this funtion towards "x":
My tutor reaches the following expressions but i get something else:
first partial derivation towards "x":
second partial derivation towards "x":
Thank you.
I tried it by using the formula f(x)/g(x) => [f(x)/g(x)]-[f(x)/g(x)] / g(x)^2 but i get something really weird.
+130466 Remember that when we are doing partial derivatives with respect to x, "y" is treated as a constant..
So we can write
(1/y) ( 1 - e-yx) = (1/y) - (1/y)e-yx
Note that the derivative of the first thing is just 0
The derivative of the second is just ... -(1/y)[-y*e-yx ] = e-yx which agrees with your tutor's answer
And taking the derivative of this, we get -y(e-yx) ...which also agrees....
+130466 Remember that when we are doing partial derivatives with respect to x, "y" is treated as a constant..
So we can write
(1/y) ( 1 - e-yx) = (1/y) - (1/y)e-yx
Note that the derivative of the first thing is just 0
The derivative of the second is just ... -(1/y)[-y*e-yx ] = e-yx which agrees with your tutor's answer
And taking the derivative of this, we get -y(e-yx) ...which also agrees....
