Quadratic

Here's a link to your answer:

https://web2.0calc.com/questions/help-please_82361

4x^2+16x-h=0

4(x^2 + 4x - x/4) = 0

x^2 + 15x/4=0

x = - 15/4

Let 7x^2 + 5x = h + 3x^2 - 11x.  What value of will h give us exactly one solution for x?

Hello Guest!

$4x^2+16x-h=0\\ x^2+4x-\frac{h}{4}=0\\ x=-2\pm\sqrt{4+\frac{h}{4}}$

$4+\dfrac{h}{4}=0\\ 4=-\dfrac{h}{4}\\ \color{blue}h=-16$

h = - 16 will  give us exactly one solution for x.

  !