Quadratic

x^2 + px + q = 0 has one negative solution and one positive solution.  If p = 3, then what are all the possible values of q?    

In other words         x² +3x + q = 0   

                               (x + 4)(x – 1)     p = –4  

                               (x + 5)(x – 2)     p = –10  

                               (x + 6)(x – 3)     p = –18  

                               (x + 7)(x – 4)     p = –28  

                               (x + 8)(x – 5)     p = –40  

I must not understand the question, because this could go on forever and  

you couldn't write down all of them if you keep writing until the end of time.  

_.

I must not understand the question, because this could go on forever and you couldn't write down all of them if you keep writing until the end of time. 

Hi Ron,

You understand the question correctly. Your answer is correct. 

The formal solution is (q < 0)

It’s relationship to (x) is:  q = -x (x + 3)

...And most importantly, you remembered to "mind your peas and queues" 

GA

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