+130466 Remember...an equation has to satisfy all values where it is defined...in this case where x > 0. So lets pick any positive number, say, 1, and see if it "works.'
7 /(1)^3 = (3/2 x √(1) + 2 / (1)^3) ???
7/1 = (3/2 + 2) ???
7 = 7/2 ???
Nope......doesn't look like it's true !!
(Actually.....your equation only works when x ≈ 1.41)
+130466 Remember...an equation has to satisfy all values where it is defined...in this case where x > 0. So lets pick any positive number, say, 1, and see if it "works.'
7 /(1)^3 = (3/2 x √(1) + 2 / (1)^3) ???
7/1 = (3/2 + 2) ???
7 = 7/2 ???
Nope......doesn't look like it's true !!
(Actually.....your equation only works when x ≈ 1.41)
