+876 There is a function that is defined the following
f1(x)=(x−1)2fn(x)=f1(fn−1(x))
What is |f7(2)|
+2407 f^1(1) = (2 - 1)^2 = 1
f^2(2) = f^1(f^1(2)) = f^1(1) = 0
f^3(2) = f^1(f^2(2)) = f^1(0) = 1
f^4(2) = f^1(f^3(2)) = f^1(1) = 0
There's a pattern. :))
It seems like when f(a) = 0, f(a+1) = 1 and when f(a) = 1, f(a+1) = 0.
So when n is odd, then the answer is 1.
If n is even, the answer is 0.
f^7(2) = 1
=^._.^=
+876 There is a reason for the pattern - can you see why? Do you see anything intesting if we generalize x for not just 2, but for all integral x? Try finding a general formula. Also notice - does your 1, 0, etc. pattern have anything to do with x=2? Maybe there is, and maybe not. Try to find out. :)
