Loading [MathJax]/jax/output/SVG/config.js
 
+0  
 
0
1416
1
avatar

sin symbol = 0.45, for 0 degrees < symbol < 90 degrees Solve equation to the nearest tenth, use given restrictions

 May 21, 2014

Best Answer 

 #1
avatar+130466 
+5

So...I'm guessing you want to find the sine of some angle in the first quadrant having a value of .45??

Using the sine inverse, we have

asin(.45)  = 26.7°

P.S....I think that "symbol" you're referring to might look like this ...θ......it's referred to as "theta" and usually represents some angle in trigonometry......

 May 21, 2014
 #1
avatar+130466 
+5
Best Answer

So...I'm guessing you want to find the sine of some angle in the first quadrant having a value of .45??

Using the sine inverse, we have

asin(.45)  = 26.7°

P.S....I think that "symbol" you're referring to might look like this ...θ......it's referred to as "theta" and usually represents some angle in trigonometry......

CPhill May 21, 2014

3 Online Users

avatar