67 water barrels need to be carried by trucks and cars. 2 trucks and 5 cars can carry them all. If 3 trucks and 4 cars are used, there will be 5 barrels left. Determine how many barrels each truck and car can carry.
+113 If we use these numbers, and do the math, then Your problem makes absolutely no sense.
If it is so that 3T + 4C leaves room for 5 more barrels, it seems to make more sense, but even en then
we come up with fractions for C, so I advice You to repost the problem with adjusted numbers.
Original numbers:
Water barrels:just numbers, Trucks: T, Cars: C
67 = 2T + 5C
67 - 5 = 3T + 5C, or 67 = 3T + 5C +5
Setting the first line equal to the second:
2T + 5C = 3T + 5C + 5, we subtract 5C on both sides, eliminiating C, and get
2T = 3T + 5, or T = -5 :: This makes absolutely NO sense.
Put this into the topmost line:
67 = -10 + 5C, 77 = 5C, C = 77/5 :: Also makes NO sense.
Adjusted numbers:
67 = 2T + 5C
67 + 5 = 3T + 5C, or 67 = 3T + 5C -5
2T + 5C = 3T + 5C - 5
2T = 3T - 5, or T = 5
Put into topmost:
67 = 10 + 5C, 5C = 57, and so C = 11 2/5 :: Also makes no sense.
