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avatar+1836 

The lottery in our state consists of two drawings. First, a MegaBall is picked from among 27 numbered b***s. Second, five WinnerBalls are picked from among 44 numbered b***s. To win the lottery, you must pick the MegaBall number correctly and also pick the numbers on the five WinnerBalls (but you don't need to get the order right for the WinnerBalls). What is the probability that the ticket I hold has the winning numbers?

 Apr 19, 2015

Best Answer 

 #3
avatar+33654 
+4

You are right Mellie.  I did this one too quickly (as I often do!).  I've now corrected it.

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 Apr 19, 2015
 #1
avatar+33654 
+12

Probability of getting Megaball:  1/27

 

Probability of getting 5 Winnerballs = (5/44)*(4/43)*(3/42)*(2/41)*(1/40)

 

Overall probability of winning = (1/27)*(5/44)*(4/43)*(3/42)*(2/41)*(1/40) = 1/29322216 ≈ 3.4*10-8

 

Edited to correct error

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 Apr 19, 2015
 #2
avatar+1836 
+9

TheprobabilitythattheMegaBallmatchesis$127$.Theprobabilitythatthe5WinnerBallsmatchis$1(445)$.Somychancesofwinningare$(127)×(1(445))=129,322,216$.

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 Apr 19, 2015
 #3
avatar+33654 
+4
Best Answer

You are right Mellie.  I did this one too quickly (as I often do!).  I've now corrected it.

.

Alan Apr 19, 2015

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