What is

$5-2(4a+1)+3a=13$

$5-(8a+2)+3a=13$

$(-8a+3a)+(5-2)=13$

$(-8+3)a+3=13$

$-5a=10$

$a=\frac{10}{-5}=-\frac{10}{5}=\boxed{-2}$

your anwer is.........

𝑎=−2     

Hey there, Caydog!

 

So let's solve this.

 

Step 1: Simplify both sides of the equation.

$5−2(4a+1)+3a=13$

$5+(−2)(4a)+(−2)(1)+3a=13$ (Distribute)

$5+−8a+−2+3a=13$

$(−8a+3a)+(5+−2)=13$ (Combine Like Terms)

$−5a+3=13$

 

Step 2: Subtract 3 from both sides.

$−5a+3−3=13−3$

$−5a=10$

 

Step 3: Divide both sides by -5.

$\frac{-5a}{-5}=\frac{10}{-5}$

 

Therefore a=-2.

 

Hope this helped! :)

( ﾟдﾟ)つ Bye