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Hello,

why is the answer to this equation 400? Regardless how I try to solve it I always get 720?

Could you please show detailed steps to solving it so I could figure out where my mistake is?

Thank you!

 Jun 10, 2014

Best Answer 

 #2
avatar+130466 
+5

Let's take this step by srep  .... we have  .....

√x +√(x/4) = 30

√x +√(x)/2 = 30       multiply through by 2

2√x +√(x) = 60        subtract √(x)  from both sides

2√(x)  = 60 - √(x)     square both sides

4x  = 3600 - 120√(x)  + x        simplify

120√(x)  = 3600 - 3x         square both sides again

14400x = 12960000 - 21600x + 9x2      simplify again

9x2 - 36000x + 12960000 = 0     divide through by 9

x2 - 4000x + 1440000   = 0     factor this 

(x-400) (x - 3600) = 0    

So.....x = 400 or x = 3600

Reject 3600 since it makes the original equation untrue

So ...   x = 400 is the only solution

 Jun 10, 2014
 #1
avatar+3146 
+5

Hi,

welcome to the forum!

with  (14)×x=(12)×x your input is equal to:

x+(12)×x=30

x×(1+12)=30

x=301.5

x=20

x = 20^2 = 400

 Jun 10, 2014
 #2
avatar+130466 
+5
Best Answer

Let's take this step by srep  .... we have  .....

√x +√(x/4) = 30

√x +√(x)/2 = 30       multiply through by 2

2√x +√(x) = 60        subtract √(x)  from both sides

2√(x)  = 60 - √(x)     square both sides

4x  = 3600 - 120√(x)  + x        simplify

120√(x)  = 3600 - 3x         square both sides again

14400x = 12960000 - 21600x + 9x2      simplify again

9x2 - 36000x + 12960000 = 0     divide through by 9

x2 - 4000x + 1440000   = 0     factor this 

(x-400) (x - 3600) = 0    

So.....x = 400 or x = 3600

Reject 3600 since it makes the original equation untrue

So ...   x = 400 is the only solution

CPhill Jun 10, 2014
 #3
avatar+893 
0

Third line, 2√(x) + √(x) = 60, so 3√(x) = 60 etc. ?

 Jun 10, 2014

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