(y-3)^2=8(x-5)
Let's see how Melody arrived at this......
Writing this in a slightly different form, we have
(y-3)^2=4p(x-5) where "p" is the distance (horizontal, in this case) between the x coordinate of the vertex and the x coordinate of the focal point.
So...we have.....
4p = 8 ..... and solving for "p" we have
p = 2 ........i.e., the focal point is 2 units to the "right" from the vertex......thus......
The vertex is (5,3) and the focus is (7,3)......just as Melody found !!!!
For a "sideways" parabola that opens to the right, we add "p" to the x coordinate of the vertex. For one that opens to the left, we subtract "p" from the x coordinate of the vertex.