3√ (128x^7) = 3√( 64*2*x^7) = 3*8√ (x^7) = 24x3√ x
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√(45x^5y^3) • √(35xy^4) ....let's simplify this one separately and then combine what we've got
√(45x^5y^3) = √(9*5*x^5*y^3)= 3x2y√(5xy)
√(35xy^4) = y2√(35x)
So multiplying both of these, we have
3x2y3√(175x2y) = 3x3y3√(25*7*y) = 5*3x3y3√(7y) = 15x3y3√(7y)
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√50x^6/√2x^4 ........we can write this as √(50x^6/(2x^4)) ....and simplifying, we have
√(25x^2) = 5x .........pretty easy, once you simplify, huh??
